This function accepts number format year as a parameter and returns true if year is a leap year else it returns false.
Function
function isLeapYear($year) {
if (($year % 4) != 0){
return false;
}
if ($year % 400 == 0) {
return true;
} else if (($year > 1582) and ($year % 100 == 0)) {
return false;
}
}
Calling The function
echo isLeapYear(2000);
Output
1

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